#include <stdio.h>

/******************************************************************
 * Try to determine the structure of the machine it is run on.
 *
 * Copyright Yves Dorfsman, December 1999
 ******************************************************************/



main (void)
{
unsigned int i,
             j,
             anint   = 1,
             base    = 1,
             sint,
             schar;


/* unsigned long long  base = 256; */

char *pt;




sint  = sizeof(int);
schar = sizeof(char);
pt    = (char *) &anint;

if (schar > 1)
  {
  fprintf(stderr, "This program was written assuming size of char to be 1 byte\n");
  return 1;
  }

for (i = 0 ; i < sint ; i++)
  {
  j    = (i > 0) ? i + 1 : 0;
  anint = anint +  base * j;
  base = base * 256;
  }

printf("\nSize of an char: %i byte\n", sizeof(char));
printf("Size of an int:  %i bytes\n", sizeof(int));
printf("Size of an long int: %i bytes\n", sizeof(long int));
printf("Size of an long long int: %i bytes\n", sizeof(long long int));
printf("Size of an float: %i bytes\n", sizeof(float));
printf("Size of an double: %i bytes\n", sizeof(double));
printf("Size of an long double: %i bytes\n", sizeof(long double));

if (*pt == 1)
  printf("\nYour machine uses a little endian architecture.\n");

else
  if (*(pt+sint-1) == 1)
    printf("\nYour machine uses a big endian architecture.\n");

  else
    printf("\nI am not entirely sure what architecture your machine is using.\n");


printf("\nIn memory, the number 0x%x is represented as the four bytes:\n", anint);
for (i = 0 ; i < sint ; i++)
  printf("%.2x   ", *(pt+i));

printf("\n\n");

}